PRE-CALC HALP AAAAAAA

[Silverhawk79]

Don't you just need to come up with a greatest common factor for all the denominators to cancel and simplify?

I've done similar problems and I remember having to do that.

Yeah, but then I forget which things to cancel out. :(

[Rius]

Dude, that's hard as heck to read, but I'll help.

[Rius]

I have a take-home test due tomorrow, and I need sum halp.

"Simplify the compound fraction. SHOW YOR WORK! (4 pts)

[(1/x + 1) + (1/2)] / (3/2X² + 4X + 2)
kthx ^_^

Much better, now to solve...

[Termanian_Knight]

Teh answer:

x³ + 3x²
----------------------------
8x⁴ + 12x³ + 4x² + 3x + 3

Multiply top and bottom by both 2x² and (x +1). That's as simple as you can get without going into the realm of imaginary numbers.

[Rius]

Teh answer:

x³ + 3x²
----------------------------
8x⁴ + 12x³ + 4x² + 3x + 3

Multiply top and bottom by both 2x² and (x +1). That's as simple as you can get without going into the realm of imaginary numbers.

??? I got:
x(3x + 2)
--------------------------------------------
8x³ + 4x² + 3

[Rius]

Teh answer:

x³ + 3x²
----------------------------
8x⁴ + 12x³ + 4x² + 3x + 3

Multiply top and bottom by both 2x² and (x +1). That's as simple as you can get without going into the realm of imaginary numbers.

??? I got:
x(3x + 2)
--------------------------------------------
8x³ + 4x² + 3

From what I see, I'm right if you solve it the way Silver wrote it, but Termanian_Knight is right if there's a parenthesis in this part...

1/(x + 1) + 1/2

[Silverhawk79]

Teh answer:

x³ + 3x²
----------------------------
8x⁴ + 12x³ + 4x² + 3x + 3

Multiply top and bottom by both 2x² and (x +1). That's as simple as you can get without going into the realm of imaginary numbers.

??? I got:
x(3x + 2)
--------------------------------------------
8x³ + 4x² + 3

Aaaaaaaa, make up your mind. D:

[Syncopathic]

repeat 9th grader: wuts a compund number/fraction O_O

[Rius]

Teh answer:

x³ + 3x²
----------------------------
8x⁴ + 12x³ + 4x² + 3x + 3

Multiply top and bottom by both 2x² and (x +1). That's as simple as you can get without going into the realm of imaginary numbers.

??? I got:
x(3x + 2)
--------------------------------------------
8x³ + 4x² + 3

Aaaaaaaa, make up your mind. D:

Look at the post above yours. ::)

[Termanian_Knight]

Aaaaaaaa, make up your mind. D:

So what is it at the beginning of the problem? (1/x) + 1 or 1/(x+1)?

[Silverhawk79]

Aaaaaaaa, make up your mind. D:

So what is it at the beginning of the problem? (1/x) + 1 or 1/(x+1)?

1/(x+1)

[Termanian_Knight]

Aaaaaaaa, make up your mind. D:

So what is it at the beginning of the problem? (1/x) + 1 or 1/(x+1)?

1/(x+1)

I'M DA WINRAR!!!1!1

The answer I posted is the 'correct' one.

[Syncopathic]

Aaaaaaaa, make up your mind. D:

So what is it at the beginning of the problem? (1/x) + 1 or 1/(x+1)?

1/(x+1)

I'M DA WINRAR!!!1!1

The answer I posted is the 'correct' one.

are you a senior? O_O

[Termanian_Knight]

Aaaaaaaa, make up your mind. D:

So what is it at the beginning of the problem? (1/x) + 1 or 1/(x+1)?

1/(x+1)

I'M DA WINRAR!!!1!1

The answer I posted is the 'correct' one.

are you a senior? O_O

I'mma a magic man. :^D

[Syncopathic]

Aaaaaaaa, make up your mind. D:

So what is it at the beginning of the problem? (1/x) + 1 or 1/(x+1)?

1/(x+1)

I'M DA WINRAR!!!1!1

The answer I posted is the 'correct' one.

are you a senior? O_O

I'mma a magic man. :^D

i wish i was magickal  at math :(