PRE-CALC HALP AAAAAAA

[Silverhawk79]

Also, I forget. Does f o g(x) mean I put f in for all the x values in g, or vice versa?

[Zovistograt]

Also, I forget. Does f o g(x) mean I put f in for all the x values in g, or vice versa?

do inner terms first.  calculate g(x) and put that in f(x).

[Silverhawk79]

Also, I forget. Does f o g(x) mean I put f in for all the x values in g, or vice versa?

do inner terms first.  calculate g(x) and put that in f(x).

So I put g(x) in for all x values of f(x)?

[Zovistograt]

Also, I forget. Does f o g(x) mean I put f in for all the x values in g, or vice versa?

do inner terms first.  calculate g(x) and put that in f(x).

So I put g(x) in for all x values of f(x)?

f o g(x) = f(g(x))

[Rius]

Aaaaaaaa, make up your mind. D:

So what is it at the beginning of the problem? (1/x) + 1 or 1/(x+1)?

1/(x+1)

I'M DA WINRAR!!!1!1

The answer I posted is the 'correct' one.

XP I'm too technical. >_>

[Silverhawk79]

Also, I forget. Does f o g(x) mean I put f in for all the x values in g, or vice versa?

do inner terms first.  calculate g(x) and put that in f(x).

So I put g(x) in for all x values of f(x)?

f o g(x) = f(g(x))

I'm dense tonight. :(

[Silverhawk79]

ALSO ONE LAST QUESTION.
How does I find f^-1(x)? :(

[Rius]

ALSO ONE LAST QUESTION.
How does I find f^-1(x)? :(

It's the inverse of the function, exempli gratia f(x) = x, f^-1(x) = 1/x; f(x) = e^x, f^-1(x) = ln x.

[Termanian_Knight]

Aaaaaaaa, make up your mind. D:

So what is it at the beginning of the problem? (1/x) + 1 or 1/(x+1)?

1/(x+1)

I'M DA WINRAR!!!1!1

The answer I posted is the 'correct' one.

XP I'm too technical. >_>

No, I wondered the same thing, but the format of the problem seemed odd on paper.

ALSO ONE LAST QUESTION.
How does I find f^-1(x)? :(

The inverse is found by substituting 'x' with 'y' in the equation and solving for 'y'. Note that 'y' really is f(x).

[Zovistograt]

ALSO ONE LAST QUESTION.
How does I find f^-1(x)? :(

It's the inverse of the function, exempli gratia f(x) = x, f^-1(x) = 1/x; f(x) = e^x, f^-1(x) = ln x.

O_o

reversing x and y is less complicated

[Silverhawk79]

ALSO ONE LAST QUESTION.
How does I find f^-1(x)? :(

It's the inverse of the function, exempli gratia f(x) = x, f^-1(x) = 1/x; f(x) = e^x, f^-1(x) = ln x.

I know, but somehow...my answer for this one problem ends up weird.

f(x) = 6/(3x+2)
f^-1(x) = x(3y+2) - 2/3
That doesn't seem right...

[えっちーせんぱい]

...this thread confuses me.

[Zovistograt]

ALSO ONE LAST QUESTION.
How does I find f^-1(x)? :(

It's the inverse of the function, exempli gratia f(x) = x, f^-1(x) = 1/x; f(x) = e^x, f^-1(x) = ln x.

I know, but somehow...my answer for this one problem ends up weird.

f(x) = 6/(3x+2)
f^-1(x) = x(3y+2) - 2/3
That doesn't seem right...

f(x) = 6/(3x+2)
y = 6/(3x+2)
x = 6/(3y+2)

and solve that for x.

[Silverhawk79]

ALSO ONE LAST QUESTION.
How does I find f^-1(x)? :(

It's the inverse of the function, exempli gratia f(x) = x, f^-1(x) = 1/x; f(x) = e^x, f^-1(x) = ln x.

I know, but somehow...my answer for this one problem ends up weird.

f(x) = 6/(3x+2)
f^-1(x) = x(3y+2) - 2/3
That doesn't seem right...

f(x) = 6/(3x+2)
y = 6/(3x+2)
x = 6/(3y+2)

and solve that for x.

That's what I just did. psyduck;

[Rius]

ALSO ONE LAST QUESTION.
How does I find f^-1(x)? :(

It's the inverse of the function, exempli gratia f(x) = x, f^-1(x) = 1/x; f(x) = e^x, f^-1(x) = ln x.

I know, but somehow...my answer for this one problem ends up weird.

f(x) = 6/(3x+2)
f^-1(x) = x(3y+2) - 2/3
That doesn't seem right...

f(x) = 6/(3x+2)
y = 6/(3x+2)
x = 6/(3y+2)

and solve that for x.

That's what I just did. psyduck;

Then you should have gotten  f^{-1(x) = 2x - 2/3;}