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Generally Speaking => Power On => Topic started by: Shujinco2 on May 07, 2008, 12:26:20 PM

Title: Do any of you see a flaw/agree with this theory?
Post by: Shujinco2 on May 07, 2008, 12:26:20 PM
The theory: The smallest possible decimal is a 0, followed by a decimal point, followed by an infinite amount of zeroes, and then followed by a one. Like this:

0.01

Note: For those who don't know, the line under the zero indicates an infinite amount.


Do any of you see any flaws in this theory?
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Ridley on May 07, 2008, 12:43:17 PM
Quote from: Shujinco on May 07, 2008, 12:26:20 PM
The theory: The smallest possible decimal is a 0, followed by a decimal point, followed by an infinite amount of zeroes, and then followed by a one. Like this:

0.01

Note: For those who don't know, the line under the zero indicates an infinite amount.


Do any of you see any flaws in this theory?

How is it even possible to stick a 1 in there when there is suposed to be never ending 0s.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Shujinco2 on May 07, 2008, 12:46:27 PM
Quote from: Ridley on May 07, 2008, 12:43:17 PM
Quote from: Shujinco on May 07, 2008, 12:26:20 PM
The theory: The smallest possible decimal is a 0, followed by a decimal point, followed by an infinite amount of zeroes, and then followed by a one. Like this:

0.01

Note: For those who don't know, the line under the zero indicates an infinite amount.


Do any of you see any flaws in this theory?

How is it even possible to stick a 1 in there when there is supposed to be never ending 0s.
Because it's the smallest decimal.

In my theory, this is equivalent to one part of time.

However, this is only a theorized decimal.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: BOSSNIG on May 07, 2008, 12:49:10 PM
The repeating sign goes above the number. That theory is very much correct.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Riosan on May 07, 2008, 01:01:49 PM
The _ under the 0 symbolizes that there are infinite 0s, and that it never ends. How, then, could there be a 1 at the end?
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Shujinco2 on May 07, 2008, 01:08:41 PM
Quote from: Riosan on May 07, 2008, 01:01:49 PM
The _ under the 0 symbolizes that there are infinite 0s, and that it never ends. How, then, could there be a 1 at the end?
That was bothering me too. If only there was a way to symbolize "Infinity minus 1" in a decimal, to indicate an occupied place value. (Hence the 1.)
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: BOSSNIG on May 07, 2008, 01:14:22 PM
Quote from: Riosan on May 07, 2008, 01:01:49 PM
The _ under the 0 symbolizes that there are infinite 0s, and that it never ends. How, then, could there be a 1 at the end?
The zeros repeat forever in the same spot, the one always being at the end of them all.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Shujinco2 on May 07, 2008, 01:16:19 PM
Quote from: Darklink on May 07, 2008, 01:14:22 PM
Quote from: Riosan on May 07, 2008, 01:01:49 PM
The _ under the 0 symbolizes that there are infinite 0s, and that it never ends. How, then, could there be a 1 at the end?
The zeros repeat forever in the same spot, the one always being at the end of them all.
Yeah, that makes sence too. :-\

Still working out the kinks. :D
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Zovistograt on May 07, 2008, 01:17:51 PM
that would be the same as

lim (1/10^(n-1))
n->∞

right?

in that case, it sure is the smallest.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Shujinco2 on May 07, 2008, 01:24:07 PM
Quote from: Zovistograt on May 07, 2008, 01:17:51 PM
that would be the same as

lim (1/10^(n-1))
n->∞

right?

in that case, it sure is the smallest.
I believe so. Except, what is "lim"? I've never heard of that term before. ????

And if this were to be offical (Which I'm pretty sure it already is. :D ), which term would be used, mine or yours?
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Red on May 07, 2008, 01:26:20 PM
Infinity is undefined in some senses. For instance infinity minus one, plus one, divided by two or multiplied by two is still infinity. It's like dividing by zero. only won't create a black hole. Undefined. Therefore the "one" would never come. I see where your theory is coming from (I had a similar one at one point) but it just doesn't work out when you implement higher mathematics :-\ Zovistograt is right, in that case it is the smallest, but there are major flaws that you are just dodging around.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: sonicdude164 on May 07, 2008, 01:27:18 PM
Yeah, I think so. Just like .9=1
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Red on May 07, 2008, 01:29:17 PM
Quote from: sonicdude164 on May 07, 2008, 01:27:18 PM
Yeah, I think so. Just like .9=1
Or like how 1/3 x 3 = 1 even though 1/3=.3
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Zovistograt on May 07, 2008, 01:30:55 PM
Quote from: Shujinco on May 07, 2008, 01:24:07 PM
Quote from: Zovistograt on May 07, 2008, 01:17:51 PM
that would be the same as

lim (1/10^(n-1))
n->∞

right?

in that case, it sure is the smallest.
I believe so. Except, what is "lim"? I've never heard of that term before. ????

And if this were to be offical (Which I'm pretty sure it already is. :D ), which term would be used, mine or yours?
limit.  It reads as "as n approaches infinity, this thing will approach this number"...in this case, zero, but it just never gets there.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Shujinco2 on May 07, 2008, 01:34:51 PM
Quote from: Zovistograt on May 07, 2008, 01:30:55 PM
Quote from: Shujinco on May 07, 2008, 01:24:07 PM
Quote from: Zovistograt on May 07, 2008, 01:17:51 PM
that would be the same as

lim (1/10^(n-1))
n->∞

right?

in that case, it sure is the smallest.
I believe so. Except, what is "lim"? I've never heard of that term before. ????

And if this were to be offical (Which I'm pretty sure it already is. :D ), which term would be used, mine or yours?
limit.  It reads as "as n approaches infinity, this thing will approach this number"...in this case, zero, but it just never gets there.
Oh, I see. In this case, 0 is the limit, and multiplying (1/10^(n-1)) by infinity would get you 0, but since it's, well, infinity, you will never reach zero, correct? Also, if I'm correct, would that mean it's possible to get every number between X and 0 without ever actually reaching 0? Because if that's true, that plays well in my interpritation of time. 8)

But wait, wouldn't it be ((1/10)^(n-1)) instead of (1/10^(n-1)). I think, going by the order of opperations, wouldn't you raise 10 to the power of (n-1) and THEN divide it into 1 via your example? Or maybe it doesn't matter either way? :D
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Red on May 07, 2008, 01:37:03 PM
Quote from: Shujinco on May 07, 2008, 01:34:51 PM
Quote from: Zovistograt on May 07, 2008, 01:30:55 PM
Quote from: Shujinco on May 07, 2008, 01:24:07 PM
Quote from: Zovistograt on May 07, 2008, 01:17:51 PM
that would be the same as

lim (1/10^(n-1))
n->∞

right?

in that case, it sure is the smallest.
I believe so. Except, what is "lim"? I've never heard of that term before. ????

And if this were to be offical (Which I'm pretty sure it already is. :D ), which term would be used, mine or yours?
limit.  It reads as "as n approaches infinity, this thing will approach this number"...in this case, zero, but it just never gets there.
Oh, I see. In this case, 0 is the limit, and multiplying (1/10^(n-1)) by infinity would get you 0, but since it's, well, infinity, you will never reach zero, correct? Also, if I'm correct, would that mean it's possible to get every number between X and 0 without ever actually reaching 0? Because if that's true, that plays well in my interpritation of time. 8)
Yes. Between any two numbers there is infinite numbers, so your, "interpretation" of time has that fact to back it up.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\ (not that I completely trust answers from a math teacher on a subject beyond what they're supposed to teach)

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Zovistograt on May 07, 2008, 01:45:33 PM
Quote from: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
it's a matter of stating it with limits or not.  You can't really state it algebraically like that, or else you're just saying what the limit is.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: bluaki on May 07, 2008, 01:49:52 PM
Quote from: Zovistograt on May 07, 2008, 01:45:33 PM
Quote from: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
it's a matter of stating it with limits or not.  You can't really state it algebraically like that, or else you're just saying what the limit is.
I don't even know what a limit is :(

I blame the slowness of the public education system
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Zovistograt on May 07, 2008, 01:52:25 PM
Quote from: bluaki on May 07, 2008, 01:49:52 PM
Quote from: Zovistograt on May 07, 2008, 01:45:33 PM
Quote from: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
it's a matter of stating it with limits or not.  You can't really state it algebraically like that, or else you're just saying what the limit is.
I don't even know what a limit is :(

I blame the slowness of the public education system
I'd send you to Wikipedia, but I realize that trying to learn math from Wikipedia is like putting an elementary school student in a college calculus class, olol

A limit is what an infinite sequence is ultimately going to reach at the infinite term, or in other words, never going to reach but come really close.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: bluaki on May 07, 2008, 01:58:18 PM
Quote from: Zovistograt on May 07, 2008, 01:52:25 PM
Quote from: bluaki on May 07, 2008, 01:49:52 PM
Quote from: Zovistograt on May 07, 2008, 01:45:33 PM
Quote from: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
it's a matter of stating it with limits or not.  You can't really state it algebraically like that, or else you're just saying what the limit is.
I don't even know what a limit is :(

I blame the slowness of the public education system
I'd send you to Wikipedia, but I realize that trying to learn math from Wikipedia is like putting an elementary school student in a college calculus class, olol

A limit is what an infinite sequence is ultimately going to reach at the infinite term, or in other words, never going to reach but come really close.
Yeah, I realized that quite a while ago. I found this (http://en.wikiversity.org/wiki/Wikiversity:Main_Page) earlier, though.

Oh, ok.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Shujinco2 on May 07, 2008, 02:12:05 PM
Quote from: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\ (not that I completely trust answers from a math teacher on a subject beyond what they're supposed to teach)

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
No, because that 1 in there states that it is, in fact, more than 0.

It would be 0 if it were 0.000...0, due to simplifying. In other words, 2 = 2.000...0 but 2 = 2.000...1, because it is ever so slightly bigger than 2.

BTW, = means Unequal to, because I don't know how to make the unequal to sign on the computer. :D
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Zovistograt on May 07, 2008, 02:15:07 PM
Quote from: Shujinco on May 07, 2008, 02:12:05 PM
Quote from: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\ (not that I completely trust answers from a math teacher on a subject beyond what they're supposed to teach)

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
No, because that 1 in there states that it is, in fact, more than 0.

It would be 0 if it were 0.000...0, due to simplifying. In other words, 2 = 2.000...0 but 2 = 2.000...1, because it is ever so slightly bigger than 2.

BTW, = means Unequal to, because I don't know how to make the unequal to sign on the computer. :D
you could just do this: =/=

But the problem is that if you say it like that, it doesn't work out too well.  That's why I'm saying that if you put it in limit form, nobody can argue that, say, 2 = 2.000...0001.  They can say the limit is (in that case) 2, but they can't say it will actually ever reach that point.

Once we start talking in terms of infinity, it gets a bit screwed up, olol.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: bluaki on May 07, 2008, 02:18:04 PM
Quote from: Zovistograt on May 07, 2008, 02:15:07 PM
Quote from: Shujinco on May 07, 2008, 02:12:05 PM
BTW, = means Unequal to, because I don't know how to make the unequal to sign on the computer. :D
you could just do this: =/=
I think != looks better for inequality, unless you're in a situation that might use factorials or whatever else that uses exclamation mark
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Shujinco2 on May 07, 2008, 02:20:46 PM
Quote from: Zovistograt on May 07, 2008, 02:15:07 PM
Quote from: Shujinco on May 07, 2008, 02:12:05 PM
Quote from: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\ (not that I completely trust answers from a math teacher on a subject beyond what they're supposed to teach)

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
No, because that 1 in there states that it is, in fact, more than 0.

It would be 0 if it were 0.000...0, due to simplifying. In other words, 2 = 2.000...0 but 2 = 2.000...1, because it is ever so slightly bigger than 2.

BTW, = means Unequal to, because I don't know how to make the unequal to sign on the computer. :D
you could just do this: =/=

But the problem is that if you say it like that, it doesn't work out too well.  That's why I'm saying that if you put it in limit form, nobody can argue that, say, 2 = 2.000...0001.  They can say the limit is (in that case) 2, but they can't say it will actually ever reach that point.

Once we start talking in terms of infinity, it gets a bit screwed up, olol.
Well, basically, 2 is a 2, a decimal point and then an infinite amount of zeroes. Going by that, wouldn't 0 be a 0, decimal point, and then infinite zeroes? Which means putting a 1 in there makes it NOT zero.

I don't know about you, but I can understand this pretty well. And doesn't it work in all cases anyway?
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: bluaki on May 07, 2008, 02:42:17 PM
Somewhat related, is it possible to express the highest possible value of x in x<1?
I'd at first expect it to be 0.999... but that's supposedly equal to one.

oh and another thing, is it possible to make an overline in bbcode?
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Zovistograt on May 07, 2008, 02:46:43 PM
Quote from: Shujinco on May 07, 2008, 02:20:46 PM
Quote from: Zovistograt on May 07, 2008, 02:15:07 PM
Quote from: Shujinco on May 07, 2008, 02:12:05 PM
Quote from: bluaki on May 07, 2008, 01:44:07 PM
I asked my 7th grade math teacher (2 years ago) when I thought the same thing if it's possible to have a nonending decimal and a digit after that and I was told it isn't :-\ (not that I completely trust answers from a math teacher on a subject beyond what they're supposed to teach)

Anyways, assuming 0.999...=1 and that 1-0.999...=0.00...1, wouldn't 0.00...1 be equal to zero?
No, because that 1 in there states that it is, in fact, more than 0.

It would be 0 if it were 0.000...0, due to simplifying. In other words, 2 = 2.000...0 but 2 = 2.000...1, because it is ever so slightly bigger than 2.

BTW, = means Unequal to, because I don't know how to make the unequal to sign on the computer. :D
you could just do this: =/=

But the problem is that if you say it like that, it doesn't work out too well.  That's why I'm saying that if you put it in limit form, nobody can argue that, say, 2 = 2.000...0001.  They can say the limit is (in that case) 2, but they can't say it will actually ever reach that point.

Once we start talking in terms of infinity, it gets a bit screwed up, olol.
Well, basically, 2 is a 2, a decimal point and then an infinite amount of zeroes. Going by that, wouldn't 0 be a 0, decimal point, and then infinite zeroes? Which means putting a 1 in there makes it NOT zero.

I don't know about you, but I can understand this pretty well. And doesn't it work in all cases anyway?
the problem is that if you go your algebraic route, someone can bring up the .9999... = 1 proof which could apply here.  Using limits takes away the need for that.

Quote from: bluaki on May 07, 2008, 02:42:17 PM
Somewhat related, is it possible to express the highest possible value of x in x<1?
I'd at first expect it to be 0.999... but that's supposedly equal to one.
let's see here


Σ (.9/(10^-n))
n = 0
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: HTA! on May 07, 2008, 02:50:33 PM
Quote from: bluaki on May 07, 2008, 02:42:17 PM
Somewhat related, is it possible to express the highest possible value of x in x<1?
I'd at first expect it to be 0.999... but that's supposedly equal to one.

oh and another thing, is it possible to make an overline in bbcode?

Depends how you look at it.. seeing as 0 .999... will never truly be 1, but in math we say it is.

As for the decimal theory...
0.0...1 is in theory the smallest decimal possible, although at the same time I guess it could be said to be impossible due to the fact that its well, infinite. In theoretical terms I suppose it is, but really there is no use for such numbers that I am currently aware of.
Title: Re: Do any of you see a flaw/agree with this theory?
Post by: Riosan on May 07, 2008, 03:01:59 PM
you all confuse me with your math talk

Quote from: Hector_the_Axe on May 07, 2008, 02:50:33 PM
Depends how you look at it.. seeing as 0 .999... will never truly be 1, but in math we say it is.

As for the decimal theory...
0.0...1 is in theory the smallest decimal possible, although at the same time I guess it could be said to be impossible due to the fact that its well, infinite. In theoretical terms I suppose it is, but really there is no use for such numbers that I am currently aware of.

I say we end the thread here. The original decimal theory is both correct in saying that 0.0...1 is the smallest number possible and that it is both impossible because nothing can come after an infinite number of 0s.