so what math are you taking

[PsychoYoshi]

Let me know when you kiddies are doing derivatives with the Chain Rule and integrals. Then we can talk.

[Hi]

Let me know when you kiddies are doing derivatives with the Chain Rule and integrals. Then we can talk.

we're doing derivatives at the end of the course
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
and i may take calculus next semester

[PsychoYoshi]

Derivatives aren't bad if you can use the Power Rule on them. It's when you throw in trig that it starts exuding major amounts of suckage. I don't think that you'll have to do anything particularly dicey if it's not a full-fledged Calculus I course.

[clompy]

honors geometry
i'm a freshman

its fairly easy and somewhat boring

but then, i like it WAY better than algebra

[Zovistograt]

pre-calculus honors and AP statistics.

[ROOk15]

Math 1 Honors

[Light]

Algebra 1.  ;D Not too hard. But I am scared of what's to come...

[Zovistograt]

Algebra 1.  ;D Not too hard. But I am scared of what's to come...

sinxcosx=(secxcotx)/(1-(cos^2)x)

SOLVE FOR X GOGOGOGOGOGOGOGO

[Pikagirl_777]

Algebra Part 1. I suck at Math, but maybe it's because Math has always been my class before lunch (No energy due to hunger) or at the end of the day (When I just want to go home) but this year, I have Math 1st period and I'm getting an A.

And I'm only a Freshmen too, just to point that out. I was talking about Middle school when I talked about Math the previous years.

[Mystic]

Honors Geometry.

[Light]

Algebra 1.  ;D Not too hard. But I am scared of what's to come...

sinxcosx=(secxcotx)/(1-(cos^2)x)

SOLVE FOR X GOGOGOGOGOGOGOGO

Umm... wild guess:

sinx=(secxcotxcosx)/(1-cosx)

I haven't got that far(in math in class), but it looks hard.

[yes.derek]

Geometry.

It's mildly difficult.

[Jono2]

sinxcosx=(secxcotx)/(1-(cos^2)x)

lol, we're on this unit right now.  you don't solve for x tho, you try to make one side equal the other.

sinxcosx = (1/cosx*cos/sinx)/1-cos^2x

sinxcosx = sinx/cosxsinx*cos^2/cosxsinx

so,

sinx (cos^2)/cosxsinx / 1-cos^2x = sinxcosx

1 - cos^2 x = sin^2x

sinx(cos^2)/cosxsinx / sin^2x = sinxcosx

sinx(cos^2)/cosxsinx * 1/sin^2x = sinxcosx

sinx(cos^2)/cosxsinx(sin^2x) = sinxcosx

sinXes cancel

cos^2/cosx(sin^2x) = sinxcosx

sinx^2 - 1 = cos^2

sin^2x / cosx(sin^2x)

sin^2xs cancel

1/cosx....


I lose. :'(

I knew how to do this stuff yesterday... >_>

it's easier on paper.


I'm in Pre-cal 12.

[blue_slime]

abstract algebra and linear algebra

[Termanian_Knight]

Calculus. It's so-so. I'm getting an A- in it so far though.  :-\