The NSFCD Tater Instigator- No Descriptions Required

[Syncopathic]

http://mexicanspaceprogram.ytmnd.com/


I love that song...

Reminds me of this one time i got drunk and this girl kept rejecting me...

Where was I?

Everywhere...
how do you get your ONLINE thing to look like that?

[Mystic]

http://mexicanspaceprogram.ytmnd.com/


I love that song...

Reminds me of this one time i got drunk and this girl kept rejecting me...

Where was I?

Everywhere...
how do you get your ONLINE thing to look like that?

Eh?

[Syncopathic]

http://mexicanspaceprogram.ytmnd.com/


I love that song...

Reminds me of this one time i got drunk and this girl kept rejecting me...

Where was I?

Everywhere...
how do you get your ONLINE thing to look like that?

Eh?

You know, where it says if you're online, how do you change it?

[Mystic]

http://mexicanspaceprogram.ytmnd.com/


I love that song...

Reminds me of this one time i got drunk and this girl kept rejecting me...

Where was I?

Everywhere...
how do you get your ONLINE thing to look like that?

Eh?

You know, where it says if you're online, how do you change it?

I dunno what you're talking about. You mean the little picture? I think it's a rank thing or sumtin.

[Nox]

hi

[Mystic]

i detect bad grammar.

[Java]

hi

bye

[Nox]

hi

bye

ok

[Java]

hi

bye

ok

ko

[Kayo]

hi

bye

ok

ko

kok


that sounds too much like cock

[Zovistograt]

o hai I need statistics help D:

How do I find what sample size is needed so that a certain proportion (like 95%) of all samples are within a certain range of the true mean (like one standard deviation or something) if the data is normally distributed?  I know I have to work backwards somehow, but...???????

ooh nevermind I got it

.95/2 = .475
.5000 - .475 = .025
.5000 + .475 = .975
-1.90 < z < 1.90
(19.22-18.22)/(11.399/(n)) = 1.9
1/(11.399/(n)) = 1.9
(n)/11.399 = 1.9
(n) = 21.6581
n  469


I feel so complete olol...all question marks except for the last one are radicals, last one is approximately equal sign (squiggly)

[えっちーせんぱい]

...?

[not famy]

...?

lol bruce campbell

[Java]

.95/2 = .475
.5000 - .475 = .025
.5000 + .475 = .975
-1.90 < z < 1.90
(19.22-18.22)/(11.399/(n)) = 1.9
1/(11.399/(n)) = 1.9
(n)/11.399 = 1.9
(n) = 21.6581
n  469

That scares me.
;_______;

[Oren]

o hai I need statistics help D:

How do I find what sample size is needed so that a certain proportion (like 95%) of all samples are within a certain range of the true mean (like one standard deviation or something) if the data is normally distributed?  I know I have to work backwards somehow, but...???????

ooh nevermind I got it

.95/2 = .475
.5000 - .475 = .025
.5000 + .475 = .975
-1.90 < z < 1.90
(19.22-18.22)/(11.399/(n)) = 1.9
1/(11.399/(n)) = 1.9
(n)/11.399 = 1.9
(n) = 21.6581
n  469


I feel so complete olol...all question marks except for the last one are radicals, last one is approximately equal sign (squiggly)

make it go away!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!