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guyz im failing algebra

Started by not famy, November 18, 2007, 11:44:46 AM

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Java

Quote from: famy on November 18, 2007, 02:12:35 PM
Quote from: Java_Java on November 18, 2007, 02:11:36 PM
Quote from: Java_Java on November 18, 2007, 02:08:52 PM
Quote from: famy on November 18, 2007, 01:49:57 PM
uhh


i got rly weird answer 4 dat
I'm in Algebra II too and I have a C- :(

But I think I can solve that problem...
You have to switch the middle two terms so it says:
2x - 5x + 18x2 + 9

Then you factor each of the underlined.
So you factor out an X in the first one and a 9 in the second one.

x(2-5) + 9(2x +1)

I hope I got that right.


Forget it. I guess I got that wrong :(

Ugh..this is why I have a C-
no its right
Really?

Hi

you can't use the factor theorem in this case, because there are no real roots to this equation
I always use the factor theorem instead of the sum and difference of cubes. I can't factor cubics right. :(

not famy


not famy

Quote from: PLAYGIRL on November 18, 2007, 02:15:54 PM
you can't use the factor theorem in this case, because there are no real roots to this equation
I always use the factor theorem instead of the sum and difference of cubes. I can't factor cubics right. :(
i cant do anything right  :(

Friendly Hostile

#64
Quote from: famy on November 18, 2007, 01:49:57 PM
uhh



Really?

Change to 18x2-3x+9
Factor out a 3
so it becomes 3(6x2-x+3)
Then use quadratic formula.


You get imaginary numbers for your answers, so if its asking for those, give them, if not, there is no real answer.

Hi

Quote from: Friendly Hostile on November 18, 2007, 02:21:17 PM

Quote from: famy on November 18, 2007, 01:49:57 PM
uhh



Really?

Change to 18x2-3x+9
Factor out a 3
so it becomes 3(6x2-x+3)
Then use quadratic formula.

It looks like they are just factoring.

Friendly Hostile

#66
Quote from: famy on November 18, 2007, 12:33:41 PM
k guyz how i factor this i got an answer but i dont think its rite

its easy problem


oh that.

Should factor into (x2+3)(x+7)(5x+3)

Hi

#67
Quote from: Friendly Hostile on November 18, 2007, 02:27:41 PM
Quote from: famy on November 18, 2007, 12:33:41 PM
k guyz how i factor this i got an answer but i dont think its rite

its easy problem


oh that.

Should factor into (x2+3)(x+7)(5x+3)
uh no
It will factor out to (x+3)2(x+1)
I used the factor theorem, because it is easier.

Friendly Hostile

Quote from: PLAYGIRL on November 18, 2007, 02:28:23 PM
Quote from: Friendly Hostile on November 18, 2007, 02:27:41 PM
Quote from: famy on November 18, 2007, 12:33:41 PM
k guyz how i factor this i got an answer but i dont think its rite

its easy problem


oh that.

Should factor into (x2+3)(x+7)(5x+3)
uh no
i havent done this in liek 3 years srry

Hi

Quote from: Friendly Hostile on November 18, 2007, 02:29:03 PM
Quote from: PLAYGIRL on November 18, 2007, 02:28:23 PM
Quote from: Friendly Hostile on November 18, 2007, 02:27:41 PM
Quote from: famy on November 18, 2007, 12:33:41 PM
k guyz how i factor this i got an answer but i dont think its rite

its easy problem


oh that.

Should factor into (x2+3)(x+7)(5x+3)
uh no
i havent done this in liek 3 years srry

how do you not touch algebra ii for three years

not famy

Quote from: PLAYGIRL on November 18, 2007, 02:28:23 PM
Quote from: Friendly Hostile on November 18, 2007, 02:27:41 PM
Quote from: famy on November 18, 2007, 12:33:41 PM
k guyz how i factor this i got an answer but i dont think its rite

its easy problem


oh that.

Should factor into (x2+3)(x+7)(5x+3)
uh no
It will factor out to (x+3)2(x+1)
I used the factor theorem, because it is easier.
r u shur i got his answer 2

well i almost got it

Hi

ya me sure
me going to scan pretty drawing ^_^

Rius

Quote from: PLAYGIRL on November 18, 2007, 02:28:23 PM
Quote from: Friendly Hostile on November 18, 2007, 02:27:41 PM
Quote from: famy on November 18, 2007, 12:33:41 PM
k guyz how i factor this i got an answer but i dont think its rite

its easy problem


oh that.

Should factor into (x2+3)(x+7)(5x+3)
uh no
It will factor out to (x+3)2(x+1)
I used the factor theorem, because it is easier.
Woah, that's right! :O
Congrats!

Friendly Hostile

Quote from: PLAYGIRL on November 18, 2007, 02:30:45 PM
Quote from: Friendly Hostile on November 18, 2007, 02:29:03 PM
Quote from: PLAYGIRL on November 18, 2007, 02:28:23 PM
Quote from: Friendly Hostile on November 18, 2007, 02:27:41 PM
Quote from: famy on November 18, 2007, 12:33:41 PM
k guyz how i factor this i got an answer but i dont think its rite

its easy problem


oh that.

Should factor into (x2+3)(x+7)(5x+3)
uh no
i havent done this in liek 3 years srry

how do you not touch algebra ii for three years
no just factoring cubic functions
we just have our calculators do that in calculus

not famy

Quote from: Friendly Hostile on November 18, 2007, 02:37:28 PM
Quote from: PLAYGIRL on November 18, 2007, 02:30:45 PM
Quote from: Friendly Hostile on November 18, 2007, 02:29:03 PM
Quote from: PLAYGIRL on November 18, 2007, 02:28:23 PM
Quote from: Friendly Hostile on November 18, 2007, 02:27:41 PM
Quote from: famy on November 18, 2007, 12:33:41 PM
k guyz how i factor this i got an answer but i dont think its rite

its easy problem


oh that.

Should factor into (x2+3)(x+7)(5x+3)
uh no
i havent done this in liek 3 years srry

how do you not touch algebra ii for three years
no just factoring cubic functions
we just have our calculators do that in calculus
ware mite i acquire one of these magick calculators