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guyz im failing algebra

Started by not famy, November 18, 2007, 11:44:46 AM

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not famy


Rius

I factored it to:

x2(x+7) + 3(5x+3) = 0

But that's as far as I could manually get. Sorry. :(

not famy

Quote from: NINNIN6 on November 18, 2007, 01:09:37 PM
I factored it to:

x2(x+7) + 3(5x+3) = 0

But that's as far as I could manually get. Sorry. :(
y thx u bff ^_^

that helps i think

Hi

#48
use synthetic division, sillies
so we have our zeros right
let's use the power of the factor theorem fdjlsdkjdlsjdslfjsdfjldsflksdjklds
brb making drawing
wait i don't have drawing

not famy

Quote from: PLAYGIRL on November 18, 2007, 01:40:51 PM
use synthetic division, sillies
so we have our zeros right
let's use the power of the factor theorem fdjlsdkjdlsjdslfjsdfjldsflksdjklds
im ok at the polynomial division i understand how to do that but factoring by grouping and factoring the sum or difference makes no sense to me  :-[

Hi

Quote from: famy on November 18, 2007, 01:44:13 PM
Quote from: PLAYGIRL on November 18, 2007, 01:40:51 PM
use synthetic division, sillies
so we have our zeros right
let's use the power of the factor theorem fdjlsdkjdlsjdslfjsdfjldsflksdjklds
im ok at the polynomial division i understand how to do that but factoring by grouping and factoring the sum or difference makes no sense to me  :-[
Factoring by grouping sucks. :[
I use the factor theorem, then go to that awful method.
what's the problem again i could help

not famy

uhh


i got rly weird answer 4 dat

Hi

me going to use factor theorem because this doo doo

not famy


Hi


not famy

Quote from: PLAYGIRL on November 18, 2007, 01:58:54 PM
first combine like terms :0
oh

i cant believe i forgot that
the problem makes moar sense now

Hi

 so it's 3(6x2-x+3)
you have to go into imaginary roots to solve this one

Java

#57
Quote from: famy on November 18, 2007, 01:49:57 PM
uhh


i got rly weird answer 4 dat
I'm in Algebra II too and I have a C- :(

But I think I can solve that problem...
You have to switch the middle two terms so it says:
2x - 5x + 18x2 + 9

Then you factor each of the underlined.
So you factor out an X in the first one and a 9 in the second one.

x(2-5) + 9(2x +1)

I hope I got that right.


Java

Quote from: Java_Java on November 18, 2007, 02:08:52 PM
Quote from: famy on November 18, 2007, 01:49:57 PM
uhh


i got rly weird answer 4 dat
I'm in Algebra II too and I have a C- :(

But I think I can solve that problem...
You have to switch the middle two terms so it says:
2x - 5x + 18x2 + 9

Then you factor each of the underlined.
So you factor out an X in the first one and a 9 in the second one.

x(2-5) + 9(2x +1)

I hope I got that right.


Forget it. I guess I got that wrong :(

Ugh..this is why I have a C-

not famy

Quote from: Java_Java on November 18, 2007, 02:11:36 PM
Quote from: Java_Java on November 18, 2007, 02:08:52 PM
Quote from: famy on November 18, 2007, 01:49:57 PM
uhh


i got rly weird answer 4 dat
I'm in Algebra II too and I have a C- :(

But I think I can solve that problem...
You have to switch the middle two terms so it says:
2x - 5x + 18x2 + 9

Then you factor each of the underlined.
So you factor out an X in the first one and a 9 in the second one.

x(2-5) + 9(2x +1)

I hope I got that right.


Forget it. I guess I got that wrong :(

Ugh..this is why I have a C-
no its right